A rectangular tank measuring `5mxx4. 5 mxx 2. 1 m ` is dug in the centre of the field measuring `13. 5 mxx 2. 5 m` . The earth dug out is spread evenly over the remaining portion of the field. How much is the level of the field raised?

Explanation

Area of the field = `(13.5 × 2.5) m^2 `
` 33.75 m^2`
Volume of the earth dug out = Vol. of the tank
` (5 xx 4.5 xx 2.1) m^3` = `47.25 m^3`
Area of the tank = `(5 xx 4.5) m^2 `
` 22.5 m^2`
Area on which the earth dug out has been spread
area of the field - area of the tank = `(33.75 - 22.5) m^2`
` 11.25 m^2`
Therefore Level raised
`(47.25)/(11.25)`
`4.2m`