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The theoretically computed equilibrium c...

The theoretically computed equilibrium constant for the polymerisation of formaldehyde to glucose in aqueous solution :
`6HCHO hArr C_6H_12O_6` is `1.0xx10^24` If 1 M-solution of glucose was taken, what should be the equilibrium concentration of formaldehyde ?

A

`1.6 xx 10^(22) M`

B

`1.6 xx 10^(-4) M`

C

` 6 sqrt(6xx10^(4)) xx 10^(3) M`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

A very high value of K indicates that amount of glucose dissociated into formaldehyde is negligible. Therefore , at equilibrium
`[C_(6)H_(12)O_(6)]=1.0 mol L^(-1)`
`K([C_(2)H_(12)O_(6)])/([HCHO]^(6))`
`6xx10^(22)=(1)/([HCHO]^(6))`
`[HCHO]^(6)=(1)/(6xx10^(22))`
`implies [HCHO]=1.6 xx 10^(-4) M`
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