Prove that:tan4x=(4tanx(1-tan^2x))/(1-6t...

Prove that:`tan4x=(4tanx(1-tan^2x))/(1-6tan^2x+tan^4x)`

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To prove that \( \tan 4x = \frac{4 \tan x (1 - \tan^2 x)}{1 - 6 \tan^2 x + \tan^4 x} \), we will use the double angle formula for tangent. ### Step-by-Step Solution: 1. **Start with the left-hand side**: \[ \tan 4x \] ...

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