`costheta+cos^2theta=1, asin^12theta+b sin^10 theta+c sin^8 theta+dsin^6theta=1=>(b+c)/(a+d)=`

If cos theta+ cos^2 theta=1 , prove that sin^12 theta+3sin^10 theta+3sin^8theta+sin^6theta+2sin^4theta+2sin^2theta-2=1

If costheta+cos^2theta=1, Prove that: sin^(12)theta+3sin^(10)theta+3sin^8theta+sin^6 theta+2sin^4 theta+2sin^2theta-2=1

If cos theta+cos^(2)theta=1, prove that sin^(12)theta+3sin^(10)theta+3sin^(8)theta+sin^(6)theta+2sin^(4)theta+2sin^(2)theta-2=1

If cos theta + cos^2 theta = 1, then value of sin^2 theta + sin^4 theta is (a) -1 (c) 0 (c) 1 (d) 2

If Sin theta+ Sin^(2) theta=1 and cos a cos^(12) theta+ b cos ^(12) theta+ b cos^(10) theta+ c cos^(8) theta+d cos^(6)-1 theta = then (b+c)/(a+d)

8 sin theta * cos theta * cos 2 theta * cos 4 theta = A) sin 4 theta B) sin 8 theta C) sin 16 theta D) cos 8 theta

If 2^(7)cos^(3)theta sin^(5)theta=a sin8 theta-b sin6 theta+c sin4 theta+d sin2 theta and theta is real,then the value of a+b+c+d must be

If 2^(7)cos^(3)theta sin^(5)theta=a sin8 theta-b sin6 theta+c sin4 theta+d sin2 theta and theta is real,then the value of a+b+c+d must be

Show that costheta [[costheta, sintheta],[-sintheta, cos theta]] + sin theta [[sintheta ,-cos theta],[costheta, sin theta]] =1