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E("cell")^(@)=1.1V for Daniel cell. Whic...

`E_("cell")^(@)=1.1V` for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?

A

`1.1 =k_(c)`

B

`(2.303RT)/(2F)"log"k_(c)=1.1`

C

`"log"k_(c)=(2.2)/(0.059)`

D

` "log" k_(c)=1.1`

Text Solution

Verified by Experts

At state of equilibrium
`Delta G=-RT"log"K`
`-nFE^(@)=-RT 2.303"log"k_(c)`
`E^(@)=(+RT2.303"log"k_(c))/(+2F)` (n=2 for Daniel cell)
`because` AT equilibrium `E^(@)=1.1`
`therefore ( 2.303RT)/(2F)"log"k_(c)=1.1`
`"log"k_(c)=(2.2)/(0.059)` [on solving]
Hence,option b and c are the correct choices.
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