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What does the negative sign in the expre...

What does the negative sign in the expression `E_(Zn^(2+)//Zn)^(@)=-0.76V` mean?

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Greater the negative reactivity of standard reduction potential of metal greater is its reactivity. It means that Zn is more reactive than hydrogen. When zinc electrode will be connected to standard hydrogen electrode Zn will get oxidised and `H^(+)` will get reduced. thus, zinc electrode will be the anode of the cell and hydrogen electrode will be the cathode of the cell.
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Can a solution of 1 M ZnSO_(4) be stored in a vessel made of copper ? Given that E_(Zn^(+2)//Zn)^(@) =-0.76V and E_(Cu^(+2)//Cu)^(@)=0.34 V

For a standard cell Zn(s)|Zn^(2+)(1 M)||Cu^(2+)(1 M)|Cu(s) Write the electrode reaction and cell reaction. Also find the e.m.f. of cell if ? E_(Zn^(2+)|Zn)^(@)=-0.76" V", E_(Cu^(2+)|Cu)^(@)=+0.34" V" .

For the galvanic cell Zn(s)[Zn^2+ (aq)||Ag^+(aq) Ag(s)] , G° of the reaction in joule will be E°_ (Zn^(2+)) /( Zn )= - 0.76V , E°_( Ag_+)/(Ag )= 0.80 V

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