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Show that when a string fixed at its two...

Show that when a string fixed at its two ends vibrates in 1 loops, 2 loops , 3 loops and 4 loops , the frequencies are in the ratio `1:2:3:4.`

Text Solution

Verified by Experts

Let there are n number of loops in the string.

Length corresponding each loop is `(lambda)/(2)`
Now, we can write
`" " L=(nlambda)/(2)rArrlambda=(2L)/(n)" "` [ for n loops ]
`rArr" (v)/(v)=(2L)/(n)rArr[ :. v=vlambda]`
`rArr" " v=(n)/(2L)v=(n)/(2L)sqrt((T)/(mu))" " [ :.` velocity of transverse waves =`sqrt(T//mu )`]
`rArrvpropn" " ` [ `:.` length and speed are constants ]
So, `" " v_(1):v_(2):v_(3):v_(4)=n_(1):n_(2):n_(3):n_(4)`
`" "=1:2:3:4`
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