If `tan theta=5/6` then `(12 sin theta-5cos theta)/(12sin theta+5cos theta)=`

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If 5tan theta=4 then value of ((5sin theta-3cos theta)/(5sin theta+3cos theta))=

If 3 cot theta = 5, then (5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta)

If 2 sin theta=5 cos theta , then (sin theta+cos theta)/(sin theta-cos theta) is equal to: यदि 2 sin theta=5 cos theta है, तो (sin theta+cos theta)/(sin theta-cos theta) का मान किसके बराबर होगा ?

If tan theta=5/12 then sin theta=

If 5 cos theta = 6 , sin theta , evalutate : (12 sin theta - 3cos theta)/(12 sin theta + 3 cos theta)