If `int cos^(-1)x+cos^(-1)sqrt(1-x^2) dx= Ax+f(x)sin^(-1)x-2sqrt(1-x^2)+c` then

Method of integration by parts : int(cos^(-1)x+cos^(-1)sqrt(1-x^(2)))dx=Ax+f(x)sin^(-1)x-2sqrt(1+x^(2))+c,AAx""in[-1,0) then ..........

int(1)/(cos^(-1)x.sqrt(1-x^(2)))dx=

int(1)/(cos^(-1)x.sqrt(1-x^(2)))dx=

int(x+cos^(-1)x)/(sqrt(1-x^(2)))dx

If int sin^(-1)x cos^(-1)xdx=f^(-1)(x)[Ax-xf^(-1)(x)-2sqrt(1-x^(2))]+2x+C, then f(x)=sin x(b)f(x)=cos xA=(pi)/(4)(d)A=(pi)/(2)

int sin^(-1)x cos^(-1)xdx=f^(-1)(x)[(pi)/(2)x-xf^(-1)(x)-2sqrt(1-x^(2))]+2x+c, then f(x) is equal to

If int sin^(-1)x cos^(-1)x dx=f^(-1)(x)[Ax-xf^(-1)(x)-2sqrt(1-x^(2))]+(pi)/(2)sqrt(1-x^(2))+2x+C, then

int(tan(cos^(-1)x)+cot(sin^(-1)x))/(sqrt(1-x^(2)))dx=

int(x)/(sqrt(1-x^(2))*cos^(2)sqrt(1-x^(2)))dx=

If int (x +(cos^-1 3x)^2)/sqrt(1 - 9x^2) dx = A sqrt(1 - 9x^2) + B (cos^-1 3x)^3 + c then A, B are respectively