If the straight line `(2x + 3y +4) +lambda (6x -y + 12) = 0` is parallel to y-axis then `lambda=`

What is the value of lambda if the straight line (2x + 3y +4) +lambda (6x - y + 12)=0 is parallel to y axis?

The line (8x + 3y - 15) + lambda (3x - 8y +2) = 0 is parallel to X-axis . Find lambda .

Find the value of lambda , if the line x - 3y + 4 + lambda (8x - 3y + 2) = 0 is parallel to the X-axis .

The line (5x-8y+11)lambda+(8x-3y+4)=0 is parallel to x -axis,then value of lambda is

The value of k such that the straight line (2x+3y+5)+k(x-7y+6)=0 is parallel to x-axis is

The value of the lambda if the lines (2x+3y+4)+lambda(6x-y+12)=0 are

The straight line x+y+1+ lambda (2x-y-1)=0 is bot to 2x+3y-8=0, find the value of lambda .

The value of the lambda if the lines (2+3y+4)+lambda(6x-y+12)=0 are