Two coins are tossed simultaneous 1000 times with the following frequencies of different outcomes: Two heads: 210 times One head:  550 times No head: 240 times Find the probability of occurrence of each of these events.

Explanation

Two coins are tossed simultaneously `1000` times.
Total number of trails =`1000`
Let A: The event of getting at least `1` head.
B: The event of getting at most `1` head.
Number of trials of getting at least `1` head = the sum of the number of trials of getting `1` head and the number of trials of getting `2` heads.
Number of trails of getting at least `1` head
=`310+350=660`
Number of trials of getting at most `1` head = the sum of the number of trials of getting `0` head and the number of trials of getting `1` head.
Number of trails of getting at most `1` head =`340+310=650`
(i)P(A)= no. of getting trails at least `1`/total number of trails
=`660/1000=0.66`
P(B)=no. of getting trails at most `1`/total number of trails
=`650/1000=0.65`.