`(5)/(4+(7)/(4-(10)/(11)))=?`

Multiply: -(3)/(5)by-(4)/(7)(ii)-(15)/(11)by7

Evaluate : (i) (3)/(4)-(4)/(5) (ii) -3-(4)/(7) (iii) (7)/(24)-(19)/(36) (iv) (14)/(15)-(13)/(20) (v) (4)/(9)-(2)/(-3) (vi) (7)/(11)- (-4)/(-11) (vii) (-5)/(14) -(-2)/(7) (viii) (-5)/(-8)-(-3)/(4)

Verify the following: (i) ((3)/(4)+(-2)/(5))+(-7)/(10)=(3)/(4)+((-2)/(5)+(-7)/(10)) (ii) ((-7)/(11)+(2)/(-5))+(-13)/(22)=(-7)/(11)+((2)/(-5)+(-13)/(22)) (iii) -1+((-2)/(3)+(-3)/(4))=(-1+(-2)/(3))+(-3)/(4)

The largest of the fractions (4)/(5), (4)/(7), (4)/(9) (4)/(11) is

Find the sum of the infinite series 1-(4)/(5)+(4.7)/(5.10)-(4.7.10)/(5.10.15)+………

Multiply: (7)/(11)by(5)/(4) (ii) (5)/(7)by(-3)/(4)

(5)/(1^(2)*4^(2))+(11)/(4^(2)*7^(2))+(17)/(7^(2)*10^(2))+

The solution set of the inequality log_(10)(x^(2)-16)<=log_(10)(4x-11) is 4,oo) (b) (4,5)(c)((11)/(4),oo)(d)((11)/(4),5)