Home
Class 14
MATHS
5795+3806=4072+?...

`5795+3806=4072+?`

Promotional Banner

Similar Questions

Explore conceptually related problems

If x% of (12)/(5) is (18)/(25), then x=30 (b) 4072 (d) 50

The resistance of the platinum wire of a platinum resistance thermometer at the ice point is 5Omega and at steam point is 5.23 Omega . When it is inserted in a hot bath, the resistance of the wire is 5.795 Omega . Calculate the temperature of the bath.

The resistance of a platinum wire of platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.23 Omega . When therometer is insertes in a hot bath, the resistance of the platinum wire is 5.795 Omega . Calculate the temperature of the bath?

The resistance of the platinum wire of a platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.39 Omega . When the thermometer is inserted in a hot bath, the resistance of the platinum wire is 5.795 Omega . Calculate the temperature of the bath.

The resistance of a platinum wire of platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.23 Omega . When therometer is insertes in a hot bath, the resistance of the platinum wire is 5.795 Omega . Calculate the temperature of the bath?

The resistance of a platinum wire of platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.23 Omega When the thermometer is inserted in a hot bath,the resistance of the platinum wire is 5.795 Omega .Calculate the temperature of the both.

The resistance of the platinum wire of a platinum resistance thermometer at the ice point is 5 Omega and at steam point is 5.39 Omega . When the thermometer is inserted in a hot bath, the resistance of the platinum wire is 5.795 Omega . Calculate the temperature of the bath.