s" at "A=[[1,2],[4,2]]" ."

The relation S is defined on set A={1,2,4,8} as S={(1,1)(2,2)(4,4)(8,8),(1,2),(1,4),(4,8)} then [A] S is reflexive and symmetric but not transitive [B] S is not reflexive,not symmetric,no transitive [C] S is not symmetric and transitive but reflexive [D] S is equivalance

An automobile company uses three types of steel S_1, \ \ S_2\ a n d\ S_3 for producing three types of cars C_1,\ \ C_2\ a n d\ C_3 . Steel requirements (in tons) for each type of cars are given below: [[Steel Cars, C_1, C_2, C_3], [S_1, 2, 3, 4], [S_2, 1, 1, 2], [S_3, 3, 2, 1]] Using Cramers rule, find the number of cars of each type which can be produced using 29, 13 and 16 tonnes of steel of three types respectively.

The quantum numbers of six elements are given below. Arrange them in order of increasing energies. If any of these combinations has/have the same energies, list them. {:((1) n = 4 ",", l = 2",", m_l=-2",", m_s = - 1/2),((2) n = 3 ",", l = 2",", m_l=0",", m_s = + 1/2),((3) n = 4 ",", l = 1",", m_l= 0",", m_s = + 1/2),((4) n = 3 ",", l = 2",", m_l=-2",", m_s = - 1/2),((5) n = 3 ",", l = 1",", m_l=-1",", m_s = + 1/2),((6) n = 4 ",", l = 1",", m_l=0",", m_s = + 1/2):}

The set of Quantum numbers that is not possible for a d-electron (A) n=3, l=2, m=0, s=+1/2 (B) n=2, l=2, m=-2, s=+1/2 (C) n=4, l=2;m=+2, s=+1/2 (D) n=4, l=2, m=-1, s=-1/2

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists: 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2 3. n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2 4. n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2 5. n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2 6. n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2

The quantum numbers of six electrons are given below. Arrange them in order of increasing energies. If any of these combination(s) has/have the same energy lists: 1. n=4 , l=2 , m_(i) =-2, m_(s) =-1//2 2. n=3 , l=2 , m_(l) =1 , m_(s) =+1//2 3. n=4 , l=2 ,m_(l)=-2, m_(s) =-1//2 4. n=3 , l= 2, m_(i) =-1 , m_(s) = +1//2 5. n=3 , l=1 , m_(l) =-1 , m_(s) = +1//2 6. n=4 , l= 1 , m_(l) =0 , m_(s) =+1//2