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Show that the diagonals of a square are ...

Show that the diagonals of a square are equal and bisect each other at right angles.

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To show that the diagonals of a square are equal and bisect each other at right angles, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Square**: Let the square be represented as ABCD, where A, B, C, and D are the vertices of the square. 2. **Identify the Diagonals**: The diagonals of the square are AC and BD. ...
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RD SHARMA-QUADRILATERALS-All Questions
  1. In Figure, A B C D is a parallelogram in which /A=60^0 . If the bisect...

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  2. In figure, Show that if the diagonals of a quadrilateral are equal and...

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  3. Show that the diagonals of a square are equal and bisect each other at...

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  4. Show that if the diagonals of a quadrilateral bisect each other at r...

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  5. A quadrilateral is a parallelogram, if its one pair of opposite sides ...

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  6. In Figure, A B C D is a parallelogram and X ,Y are the mid=points of s...

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  7. In a triangle A B C median A D is produced to X such that A D=D Xdot P...

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  8. In Figure, P Q R S is a parallelogram, P O and Q O are, respectively, ...

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  9. The diagonals of a parallelogram A B C D intersect at OdotA line throu...

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  10. In Figure, A B C D is a parallelogram and /D A B=60^0dot If the bisect...

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  11. In a parallelogram A B C D , the bisector of /A also bisects B C at Xd...

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  12. A B C D is a parallelogram. L and M are points on A B and D C respecti...

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  13. P Q R S is a parallelogram. P X and QY are respectively, the perpendic...

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  14. A B C D is a parallelogram. A B is produced to E so that B E=A B . Pro...

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  15. If A B C D is a quadrilateral in which A B C D and A D=B C , prove th...

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  16. Find the measure of all the angles of a parallelogram, if one angle is...

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  17. The perimeter of a parallelogram is 22c mdot If the longer side measur...

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  18. In Figure, A B C D is a parallelogram in which P is the mid-point of D...

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  19. A B C is a triangle. D is a point on A B such that A D=1/4A B and E is...

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  20. Show that the line segments joining the mid-points of the opposite s...

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