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In a triangle A B C median A D is produc...

In a triangle `A B C` median `A D` is produced to `X` such that `A D=D Xdot` Prove that `A B X C` is a parallelogram.

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Given : In `/_\ABC, AD` is median and `AD` is produced to `X` such that `DX=AD`
To prove : `ABXC` is a parallelogram.
Construction : Join `BX` and `CX`.
Proof : In `/_\ABD and /_\CDX`,
`AD=DX` (Given)
`BD=DC` (`D` is mid-points)
`/_ADB=/_CDX` (Vertically opposite angles)
`:./_\ABD~=/_\CDX` (By `SAS`)
`:. AB=CX` (By `CPCT`)
and `/_ABD=/_DCX`
But these are alternate angles.
`:.AB||CX` and `AB=CX`
`:. ABXC` is a parallelogram.
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