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FOIL the following expressions. (x+7)(...

FOIL the following expressions.
`(x+7)(3+x)`

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To FOIL the expression \((x + 7)(3 + x)\), we will follow the steps of the FOIL method, which stands for First, Outside, Inside, and Last. ### Step-by-Step Solution: 1. **Identify the terms**: - The first expression is \(x + 7\). - The second expression is \(3 + x\). 2. **Apply the FOIL method**: - **First**: Multiply the first terms of each binomial: \[ x \cdot x = x^2 \] - **Outside**: Multiply the outer terms: \[ x \cdot 3 = 3x \] - **Inside**: Multiply the inner terms: \[ 7 \cdot x = 7x \] - **Last**: Multiply the last terms of each binomial: \[ 7 \cdot 3 = 21 \] 3. **Combine all the results**: - Now, we combine all the products obtained from the FOIL method: \[ x^2 + 3x + 7x + 21 \] 4. **Combine like terms**: - Combine the \(3x\) and \(7x\): \[ 3x + 7x = 10x \] - Therefore, the expression simplifies to: \[ x^2 + 10x + 21 \] ### Final Answer: \[ x^2 + 10x + 21 \]
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