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P square Q=P+2Q for all integers P and Q...

`P square Q=P+2Q` for all integers P and Q
`{:("Quantity A","Quantity B"),(11 square5, 5square 11):}`

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To solve the problem, we need to evaluate the two expressions defined by the operation \( P \square Q = P + 2Q \) for the given values in Quantity A and Quantity B. ### Step-by-step Solution: 1. **Identify the operation**: The operation defined is \( P \square Q = P + 2Q \). 2. **Evaluate Quantity A**: - For Quantity A, we have \( 11 \square 5 \). - According to the operation, we substitute \( P = 11 \) and \( Q = 5 \): \[ 11 \square 5 = 11 + 2 \times 5 \] - Calculate \( 2 \times 5 \): \[ 2 \times 5 = 10 \] - Now substitute back: \[ 11 \square 5 = 11 + 10 = 21 \] - Therefore, Quantity A is \( 21 \). 3. **Evaluate Quantity B**: - For Quantity B, we have \( 5 \square 11 \). - Again, using the operation, we substitute \( P = 5 \) and \( Q = 11 \): \[ 5 \square 11 = 5 + 2 \times 11 \] - Calculate \( 2 \times 11 \): \[ 2 \times 11 = 22 \] - Now substitute back: \[ 5 \square 11 = 5 + 22 = 27 \] - Therefore, Quantity B is \( 27 \). 4. **Compare the two quantities**: - Quantity A = \( 21 \) - Quantity B = \( 27 \) - Since \( 27 > 21 \), we conclude that Quantity B is greater than Quantity A. ### Final Conclusion: - Quantity A is \( 21 \) and Quantity B is \( 27 \). Thus, Quantity B is larger than Quantity A.
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