Calculate the units digit of the following products :
`4^(3)xx7^(2)xx8`

Answer

To find the units digit of the product \( 4^3 \times 7^2 \times 8 \), we can follow these steps:

### Step 1: Calculate the units digit of \( 4^3 \)
- \( 4^3 = 4 \times 4 \times 4 = 64 \)
- The units digit of \( 64 \) is **4**.

### Step 2: Calculate the units digit of \( 7^2 \)
- \( 7^2 = 7 \times 7 = 49 \)
- The units digit of \( 49 \) is **9**.

### Step 3: Identify the units digit of \( 8 \)
- The units digit of \( 8 \) is **8**.

### Step 4: Multiply the units digits obtained
- Now we need to find the units digit of the product of the units digits we calculated:
\[ 4 \times 9 \times 8 \]

### Step 5: Calculate \( 4 \times 9 \)
- \( 4 \times 9 = 36 \)
- The units digit of \( 36 \) is **6**.

### Step 6: Multiply the result by \( 8 \)
- Now we multiply the units digit \( 6 \) by \( 8 \):
\[ 6 \times 8 = 48 \]
- The units digit of \( 48 \) is **8**.

### Final Answer
- Therefore, the units digit of \( 4^3 \times 7^2 \times 8 \) is **8**.

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