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If ((1)/(2))^(y)=(1)/(4)xx2^(y), what is...

If `((1)/(2))^(y)=(1)/(4)xx2^(y)`, what is y?

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To solve the equation \(\left(\frac{1}{2}\right)^{y} = \frac{1}{4} \times 2^{y}\), we can follow these steps: ### Step 1: Rewrite the equation We start with the given equation: \[ \left(\frac{1}{2}\right)^{y} = \frac{1}{4} \times 2^{y} \] ### Step 2: Express \(\frac{1}{2}\) and \(\frac{1}{4}\) in terms of powers of 2 We know that: \[ \frac{1}{2} = 2^{-1} \quad \text{and} \quad \frac{1}{4} = 2^{-2} \] Thus, we can rewrite the left side: \[ \left(2^{-1}\right)^{y} = 2^{-2} \times 2^{y} \] ### Step 3: Simplify the left side Using the power of a power property \((a^m)^n = a^{m \cdot n}\), we have: \[ 2^{-y} = 2^{-2} \times 2^{y} \] ### Step 4: Combine the right side Using the property of exponents \(a^m \times a^n = a^{m+n}\), we combine the terms on the right: \[ 2^{-y} = 2^{-2 + y} \] ### Step 5: Set the exponents equal Since the bases are the same, we can set the exponents equal to each other: \[ -y = -2 + y \] ### Step 6: Solve for \(y\) To isolate \(y\), we can add \(y\) to both sides: \[ -y + y = -2 + y + y \implies 0 = -2 + 2y \] Now, add 2 to both sides: \[ 2 = 2y \] Finally, divide both sides by 2: \[ y = 1 \] ### Final Answer Thus, the value of \(y\) is: \[ \boxed{1} \]
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