`{:("Quantity A","Quantity B"),(2^(y),((1)/(2))^(-y)):}`

Answer

To solve the problem, we need to compare Quantity A and Quantity B:

**Given:**
- Quantity A: \( 2^y \)
- Quantity B: \( \left(\frac{1}{2}\right)^{-y} \)

**Step 1: Rewrite Quantity B using the laws of exponents.**
Using the property of exponents that states \( a^{-m} = \frac{1}{a^m} \), we can rewrite Quantity B:

\[ \left(\frac{1}{2}\right)^{-y} = \frac{1}{\left(\frac{1}{2}\right)^y} = \frac{1}{\frac{1^y}{2^y}} = \frac{2^y}{1} = 2^y \]

**Step 2: Compare Quantity A and Quantity B.**
Now we have:

- Quantity A: \( 2^y \)
- Quantity B: \( 2^y \)

Since both quantities are equal, we can conclude:

\[ \text{Quantity A} = \text{Quantity B} \]

**Final Conclusion:**
Both quantities are equal.