The number of users (non - zero ) of a social networking website doubles every 4 months.
`{:("Quantity A","Quantity B"),("Ten times the number of users","The number of users today"),("one year ago",):}`

Answer

To solve the problem, we need to compare two quantities based on the growth of users on a social networking website.

### Step-by-Step Solution:

1. **Define the Variables**:
Let the number of users one year ago be represented as \( X \).

2. **Calculate Quantity A**:
Quantity A is defined as ten times the number of users one year ago.
\[ \text{Quantity A} = 10 \times X = 10X \]

3. **Determine the Growth of Users**:
The problem states that the number of users doubles every 4 months. In one year (which is 12 months), the number of doubling periods can be calculated as:
\[ \text{Number of doubling periods} = \frac{12 \text{ months}}{4 \text{ months/doubling}} = 3 \]

4. **Calculate Quantity B**:
Since the number of users doubles three times over the year, the number of users today (Quantity B) can be calculated as:
\[ \text{Quantity B} = X \times 2^3 = X \times 8 = 8X \]

5. **Compare Quantity A and Quantity B**:
Now we compare the two quantities:
- Quantity A: \( 10X \)
- Quantity B: \( 8X \)

Since \( 10X > 8X \) (for \( X > 0 \)), we conclude that:
\[ \text{Quantity A} > \text{Quantity B} \]

6. **Final Conclusion**:
Therefore, the correct answer is that Quantity A is greater than Quantity B.

### Summary of Results:
- **Quantity A**: \( 10X \)
- **Quantity B**: \( 8X \)
- **Comparison**: \( 10X > 8X \)

### Answer:
**Quantity A is greater than Quantity B.**

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