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x^2ltxlt1 {:("Quantity A","Quantity B"...

`x^2ltxlt1`
`{:("Quantity A","Quantity B"),((x^(3)-x)(4x+3),(x^(2)+1)(4x^(2)+3x)):}`

A

Quantity A is greater.

B

Quantity B is greater.

C

The two quantities are equal.

D

The relationship cannot be determined from the infromation given.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to compare two quantities given the condition \( x^2 < x < 1 \). Let's break down the solution step by step. ### Step 1: Understand the condition The condition \( x^2 < x < 1 \) implies that \( x \) is a positive number less than 1. Since \( x^2 < x \), we can also deduce that \( x \) must be between 0 and 1. ### Step 2: Define the quantities We have two quantities to compare: - Quantity A: \( (x^3 - x)(4x + 3) \) - Quantity B: \( (x^2 + 1)(4x^2 + 3x) \) ### Step 3: Simplify Quantity A Let's simplify Quantity A: \[ x^3 - x = x(x^2 - 1) = x(x - 1)(x + 1) \] Thus, we can rewrite Quantity A as: \[ (x(x - 1)(x + 1))(4x + 3) \] ### Step 4: Simplify Quantity B Now, let's simplify Quantity B: \[ (x^2 + 1)(4x^2 + 3x) \] This expression is already simplified. ### Step 5: Compare the two quantities Now we need to compare: - Quantity A: \( x(x - 1)(x + 1)(4x + 3) \) - Quantity B: \( (x^2 + 1)(4x^2 + 3x) \) ### Step 6: Factor out common terms Notice that both quantities have a common factor of \( 4x^2 + 3x \). However, we need to analyze the first factors: - For Quantity A, the first factor is \( x(x - 1)(x + 1) \). - For Quantity B, the first factor is \( x^2 + 1 \). ### Step 7: Analyze the first factors 1. **For Quantity A**: Since \( 0 < x < 1 \), we know: - \( x - 1 < 0 \) (negative) - \( x + 1 > 0 \) (positive) - Therefore, \( x(x - 1)(x + 1) < 0 \) (since it is a product of a positive and a negative number). 2. **For Quantity B**: The first factor \( x^2 + 1 > 0 \) for all \( x \), and since \( x^2 \) is always non-negative, \( x^2 + 1 \) is always positive. ### Step 8: Conclusion Since Quantity A is negative and Quantity B is positive, we can conclude that: \[ \text{Quantity B} > \text{Quantity A} \] Thus, the answer is that Quantity B is greater than Quantity A. ### Final Answer **Quantity B is greater than Quantity A.**
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