A company has two divisions. Division A has 105 employees and an average salary of `$60,000`. Division B has 93 employees and an average salary of `$70,000.`
`{:("Quantity A","Quantity B"),("The average salary of all the","$65,000"),("employees at the company",):}`

Options

A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the infromation given.

Answer

To solve the problem, we need to calculate the average salary of all employees in the company and then compare it to the given quantity B, which is $65,000.

### Step-by-Step Solution:

1. **Calculate the total salary for Division A**:
- Division A has 105 employees with an average salary of $60,000.
- Total salary for Division A = Number of employees × Average salary
\[ \text{Total salary for Division A} = 105 \times 60,000 = 6,300,000 \]

2. **Calculate the total salary for Division B**:
- Division B has 93 employees with an average salary of $70,000.
- Total salary for Division B = Number of employees × Average salary
\[ \text{Total salary for Division B} = 93 \times 70,000 = 6,510,000 \]

3. **Calculate the total salary for both divisions**:
- Total salary for the company = Total salary for Division A + Total salary for Division B
\[ \text{Total salary for the company} = 6,300,000 + 6,510,000 = 12,810,000 \]

4. **Calculate the total number of employees**:
- Total number of employees = Number of employees in Division A + Number of employees in Division B
\[ \text{Total number of employees} = 105 + 93 = 198 \]

5. **Calculate the average salary of all employees**:
- Average salary = Total salary for the company / Total number of employees
\[ \text{Average salary} = \frac{12,810,000}{198} \approx 64,646.46 \]

6. **Compare the average salary with Quantity B**:
- Quantity A (Average salary of all employees) ≈ $64,646.46
- Quantity B = $65,000

Since $64,646.46 is less than $65,000, we conclude that Quantity B is greater.

### Final Answer:
- **Quantity A is less than Quantity B**.