`{:("Column A" , "The money John has is just","ColumnB"),(, "enough to buy him either 100",),(, "apples and 150 oranges or 50",),(,"apples and 225 oranges",),("Cost of 100 apples", ,"cost of 150 oranges"):}`

Options

A. If column A is larger
B. If column B is larger
C. If the columns are equal
D. If there is not enough information to decide

Answer

To solve the problem, we need to analyze the information given about John's purchasing options and set up equations based on the costs of apples and oranges.

### Step-by-Step Solution:

1. **Define Variables**:
Let the cost of one apple be \( A \) and the cost of one orange be \( B \).

2. **Set Up Equations**:
According to the problem, John can buy:
- 100 apples and 150 oranges, or
- 50 apples and 225 oranges.

The total cost for each option can be expressed as:
- For 100 apples and 150 oranges:
\[ \text{Total Cost} = 100A + 150B \]
- For 50 apples and 225 oranges:
\[ \text{Total Cost} = 50A + 225B \]

3. **Equate the Two Costs**:
Since both options cost the same amount of money, we can set the two equations equal to each other:
\[ 100A + 150B = 50A + 225B \]

4. **Rearrange the Equation**:
Move all terms involving \( A \) to one side and all terms involving \( B \) to the other side:
\[ 100A - 50A = 225B - 150B \]
Simplifying this gives:
\[ 50A = 75B \]

5. **Solve for \( A \)**:
Divide both sides by 50 to isolate \( A \):
\[ A = \frac{75}{50}B \]
Simplifying this further gives:
\[ A = \frac{3}{2}B \]
This is our first equation.

6. **Calculate Column A**:
Column A represents the cost of 100 apples:
\[ \text{Column A} = 100A = 100 \times \frac{3}{2}B = 150B \]

7. **Calculate Column B**:
Column B represents the cost of 150 oranges:
\[ \text{Column B} = 150B \]

8. **Compare Columns**:
We find that:
\[ \text{Column A} = 150B \quad \text{and} \quad \text{Column B} = 150B \]
Therefore, both columns are equal:
\[ \text{Column A} = \text{Column B} \]

### Conclusion:
Since both columns are equal, the answer is that the columns are equal.