Find the measure of all the angles of a parallelogram, if one angle is `24^@` less than twice the smallest angle.

Explanation

Let the smallest angle of the parallelogram be `x`.
According to the question:
The largest angle`=(2x−24^@`)
Sum of the adjacent angles of the parallelogram`=180^@`
`x+2x−24^@=180^@`
`3x=180^@+24^@`
`3x=204^@`
`x=68^@`
`therefore` The largest angle`=2(68^@-24^@)=112^@`