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Let f:R->R be given by f(x)=(x +1)^2-...

Let `f:R->R` be given by `f(x)=(x +1)^2-1, x>=-1` Then `f^(-1)(x)=` (i) `-1+sqrt(1+x)` (ii)`-1-sqrt(1+x)` (iii) does not exist as f^(-1)(x) is one one (iv) does not exist as f^(-1)(x) is onto

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