Atomic number of `Mn, Fe, Co` and `Ni` are 25, 26, 27 and 28 respectively. Which of the following outer orbital octahedral complexes have same number of unpaired electrons ?

Options

A. `[MnCl_(6)]^(3-)`
B. `[FeF_(6)]^(3-)`
C. `[CoF_(6)]^(3-)`
D. `[Ni(NH_(3))_(6)]^(2+)`

Answer

A, C

Explanation

Number of unpaired electrons = 2
Magnetic property = Paramagnetic
Thus, `[MnCl_(6)]^(3-)` and `[CoF_(6)]^(3-)` are paramagnetic having four electrons each.
Hence, correct choices are (a) and (c).