tan^(-1)(sin x)/(1+cos x)

If y=tan^(-1)((1+sin x)/(cos x))" shoe that "(dy)/(dx)= (1)/(2) .

If y=tan^(-1) ((1-sin x)/(cos x)),"then " dy/dx=

Evaluate: (i) int tan^(-1)((sin2x)/(1+cos2x))dx( ii) int cos^(-1)(sin x)dx

int tan^(-1) ((sin2x)/(1+cos 2x))dx

Evaluate the following integrals: int tan^(-1)((sin2x)/(1+cos2x))dx

Find the derivative with tan^(-1) ((sinx )/(1 + cos x)) with respect to tan^(-1) ((cos x)/(1 + sin x))

" If "I=int(cos^(3)xdx)/((sin^(4)x+3sin^(2)x+1)tan^(-1)(sin x+cos ecx)),=-A log|tan^(-1)(sin x+cos ecx)|+C" ,then A is equal "

tan^(-1)((cos x)/(1+sin x))

tan^(-1)((cos x)/(1-sin x))