f:x=cos theta-cos2 theta,y=sin theta-sin2 theta

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =

If =2cos theta-cos2 theta and y=2sin theta-sin2 theta Prove that (dy)/(dx)=tan((3 theta)/(2))

If x=cos theta-cos 2theta and y=sin theta-sin2theta , then find (dy)/(dx) .

If x=2cos theta -cos2 theta and y=2sin theta -sin2 theta , find (d^2y)/(dx^2) at theta=pi/2 .

Evaluate the following determinants: (b) |(cos theta, -sin theta),(sin theta, cos theta)| = cos theta (cos theta) - sin theta(-sin theta) = cos^(2) theta + sin^(2) theta = 1

x = cos theta - cos 2 theta, y = sin theta - sin 2 theta . then find dy/dx

If cos theta{:((cos theta, sin theta),(-sin theta, cos theta)):}+ sin theta{:((x,-cos theta),(cos theta, x)):}=I_(2) , find x.

If f (theta) = [[cos^(2) theta , cos theta sin theta,-sin theta],[cos theta sin theta , sin^(2) theta , cos theta ],[sin theta ,-cos theta , 0]] ,then f ( pi / 7) is

If f(theta)=|(cos^(2) theta, cos theta sin theta, -sin theta),(cos theta sin theta, sin^(2) theta, cos theta),(sin theta, -cos theta, 0)| then f((pi)/12)=

If f(theta)=|[cos^(2)theta,cos theta sin theta,-sin theta],[cos theta sin theta,sin^(2)theta,cos theta],[sin theta,-cos theta,0]| , then f((pi)/(12))