question based on block over wedge constrained

Questions based on block over block

Find the relation among the acceleration of blocks A and B constrained to move along the inclined surfaces of the fixed wedge shown in figure

Constrained Wedge

In the figure if block A and wedge b will move with same acceleration, then the magnitude of normal reaction between the block and the wedge will be (There is no friction between block and the wedge and the wedge moves on horizontal surface as shown.)

Constrained motion- wedge || Rod constraints

A wedge with mass M rests on a frictionless horizontal surface A block with mass m is placed on the wedge. There is no friction between the block and the wedge. A horizontal force f is applied to the wedge. What magnitude F must have if the block is to remain at constant height above the table top?

Figure shows an irregular wedge of mass m placed on a smooth horizontal surface. Part BC is rough. If the coefficient of friction between the block and wedge is mu , and the block comes to rest with respect to wedge at a point E on the rough surface then BE will be

A block of mass 2 kg is kept on a smooth wedge of mass 3 kg and wedge is kept on a rough horizontal surface. A vertical force of 60 N is applied on the minimum coefficient of friction between the wedge and horizontal surface, so that wedge remains at rest during the motion of block on the wedge ?

A block is released on the slant face of a wedge of equal mass placed on a horizontal floor. The slant face of the wedge makes an angle of 45^(@) with the floor. Coefficient of friction between all surfaces in contact is the same. Different value/ range of coefficient of friction is given in column I and corresponding consequences in column II and III (wedge is fress to move) {:(,"Column-I",,"Column-II",,"Column-III",),((I),mu=0,(i),"Work done by friction on block and wedge is negative (on each)",(P),"Centre of mass of system (block+wedge) moves rightward and downward",),((II),mu gt 1,(ii),"Work done by friction on block is negative but on wedge it is zero",(Q),"Centre of mass of system (block+wedge) moves leftward and downward",),((III),sqrt(5)-2 lt mu lt 1,(iii),"Work done by friction on block and wedge is zero (on each)",(R ),"Centre of mass of system (block+wedge) remains at rest",),((IV),mu lt sqrt(5) - 2,(iv),"Friction between the block and wedge is static and between the wedge and ground it is kinetic in nature.",(S),"Centre of mass of system (block+wedge) moves vertically downward",):} Which of the following options is the correct representaion of the case that the block slides down the wedge and wedge slide on the floor