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" (1) "intsin(x-a)/cos(x-b)dx...

`" (1) "intsin(x-a)/cos(x-b)dx`

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Knowledge Check

  • int(sin(x+a))/(cos(x-b))dx=

    A
    `x sin(a+b)+cos(a+b)log|sec(x-b)|+c`
    B
    `x sin(a-b)+cos(a-b)log|sec(x-b)|+c`
    C
    `x sin(a-b)-cos(a-b)log|sec(x-b)|+c`
    D
    `x sin(a+b)-cos(a+b)log|sec(x-b)|+c`

  • int(cos (x-a))/(cos(x-b))dx=

    A
    `xcos(a-b)+sin(b-a).log[sec(x-b)]+c`
    B
    `xsin(a-b)+cos(a-b).log[sec(x-b)]+c`
    C
    `xcos(a-b)+sin(a-b).log[sec(x-b)]+c`
    D
    `xcos(b-a)+sin(b-a).log[sec(x-b)]+c`

  • If int(k)/(sin(x-a)cos(x-b))dx=log[(sin(x-a))/(cos(x-b))]+c , then k=

    A
    `sin(a-b)`
    B
    `cos(a-b)`
    C
    `tan(a-b)`
    D
    `sec(a-b)`

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