A cell of emf 'E' is connected across a resistance R.The potential difference between the terminals of the cell is found to be "V" .The internal resistance of the cell must be:

The potential difference betwee11 the terminals of a cell in an open circuit is 2.2 V. When a resistor of 5 Omega is connected across the terminals of the cell, the potential difference between the terminals of the cell is found to be 1.8 V. The internal resistance of the cell is

A cell has emf of 2.2 V, when connected to a resistance of 5 Omega , the potential difference between the terminals of the cell becomes 2.1 V, the internal resistance for the cell is

The emf of a daniel cell is 1.08 V. When the terminals of the cells are connected to a ressitance of 3Omega , the potential difference across the terminals is found to be 0.6 V. Then the internal resistance of the cell is

The emf of a cell is 2 V. When the terminals of the cell is connected to a resistance 4Omega . The potential difference across the terminals, if internal resistance of cell is 1Omega is

A cell has an emf 1.5V. When connected across an external resistance of 2Omega , the terminal potential difference falls to 1.0V. The internal resistance of the cell is:

For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current I drawn the cell. The emf and the internal resistance of the cell are E and r, respectively. Then

A cell which has an emf 1.5 V is connection series with an external resistance of 10Omega . If the potential difference across the cell is 1.25 V, then the internal resistance of the cell is ("in" Omega)