A circular coil of radius `R`, having `n` turns carries a current 7A. The dipole moment of the coil is m and the magnetic field induction at the center is `B`. The ratio m: B is proportional to

A circular coil of radius 10 cm "and" 100 turns carries a current 1A. What is the magnetic moment of the coil?

A circular coil of radius 10 cm having 100 turns carries a current of 3.2 A. The magnetic field at the center of the coil is

A circular coil of diameter 7cm has 24 turns of wire carrying current of 0.75A . The magnetic moment of the coil is

A circular coil of n turns and radius r carries a current I. The magnetic field at the center is

A 200 turn closely wound circular coil of radius 15 cm carries a current of 4 A. The magnetic moment of this coil is

A circular coil of radius 4 cm having 20 turns carries a current of 3A.It is a magnetic field of intensity 0.5 Wb//m^(2) .The magnetic dipole moment of the coil is

A circular coil of radius 'r' having 'n' turns carries a current 'I' . The magnetic induction at the center of the coil is 'B' . Now the coil is unwound and rewound with half the original radius. If the magnetic induction at the center of the coil is to be the same, the current that should be passed through the coil is

A circular coil of wire consisting of 100 turns each of radius 8cm carries a current of 0.4A. What is the magnitude of magnetic field at the center of the coil