Home
Class 11
PHYSICS
[" 11.Two similar point charges "q(1)" a...

[" 11.Two similar point charges "q_(1)" and "q_(2)" are placed at a distance "r" apart "],[" in air.Now a slab of thickness half the separation between the "],[" charges is placed between the charges and the coulombs repulsive "],[" force is reduced in the ratio "9:4" .The dielectric constant "(k)" for "],[" such a slab is "],[[" 1) "2," 2) "4," 3) "sqrt(2)," 4) "3]]

Promotional Banner

Similar Questions

Explore conceptually related problems

Two charges are placed at a distance apart if a glas slab is placed between them force between them will

Two point charges +q and -q are placed a distance x apart. A third charge is so placed that al the three charges are in equilibrium. Then

Two point charges+ q and-q are placed at distanced apart. What are the points at which the resultant field is parallel to the line joining the two charges ?

Two similar point charges q_1 and q_2 are placed at a distance r apart in the air. The force between them is F_1 . A dielectric slab of thickness t(ltr) and dielectric constant K is placed between the charges . Then the force between the same charge . Then the fore between the same charges is F_2 . The ratio is

Two point charges 2q and 8q are placed at a distance r apart. Where should a third charge -q be placed between them so that the electrical potential energy of the system is a minimum

Two point charges +4q and +q are placed at a distance L apart. A third charge Q is so placed that all the three charges are in equilibrium. Then location. And magnitude of the third charge will be

Two points charges Q_(1) and Q_(2) placed at separation d in vacuum and force acting between them is F . Now a dielectric slab of thickness d//2 and dielectric constant K = 4 is placed between them. The new force between the charges will be