(b) `sin^(2)theta-(1)/(2)sin theta=0`

tan theta= A) (sqrt(1-sin^(2)theta))/(sin theta) , B) (1)/(sec theta) , C) (sin theta)/(sqrt(1-sin^(2)theta)) D) (1)/(sqrt(1+Cot^(2)theta)

Prove that sin^(2)theta+sin^(2)2 theta+sin^(2)3 theta+....+sin^(2)n theta=(n)/(2)-(sin n theta cos(n+1)theta)/(2sin theta)

Prove that sin theta+sin3 theta+sin5 theta+....+sin(2n-1)theta=(sin^(2)n theta)/(sin theta)

If theta in(0,2 pi) and 2sin^(2)theta-5sin theta+2>0 then the range of theta is

Let f_(n)(theta)= 2 sin . (theta)/(2) sin. (3theta)/(2) + 2 sin.(theta)/(2) sin. (5theta)/(2) + 2sin. (theta)/(2) sin. (7 theta)/(2) + ... + 2 sin (2 n+1) (theta)/(2), n in N , then which of the following is/are correct ?

If (cos theta_(1))/(cos theta_(2))+(sin theta_(1))/(sin theta_(2))=(cos theta_(0))/(cos theta_(2))+(sin theta_(0))/(sin theta_(2))=1 , where theta_(1) and theta_(0) do not differ by can even multiple of pi , prove that (cos theta_(1)*cos theta_(0))/(cos^( 2)theta_(2))+(sin theta_(1)*sin theta_(0))/(sin^(2) theta_(2))=-1

If sin theta+csc theta=2, then the value of sin(theta)/(16)sin(theta)/(8)sin(theta)/(4)sin(theta)/(2)sin2 theta is 1 b.(1)/(sqrt(2)) c.-(1)/(sqrt(2)) d.0

sin4 theta can be written as (a) 4sin theta(1-2sin^(2)theta)sqrt(1-sin^(2)theta)(b)2sin theta cos theta sin^(2)theta(c)4sin theta-6sin^(3)theta(d) None of the above

(cos^(2)theta(1-cos theta))/(sin^(2)theta(1-sin theta))=(1+sin theta)/(1+cos theta)