A particle when thrown obliquely from ground, can have a maximum horizontal range 'X'. When it is thrown vertically upwards with the same speed, the maximum height reached by the particle, will be 2 Х 2x √2

[" A particle when thrown obliquely from ground,"],[" can have a maximum horizontal range "'x'" .When "],[" it is thrown vertically upwards with the same "],[" speed,the maximum height reached by the "],[" particle,will be "],[0(x)/(2)]

When a ball is thrown vertically upwards, at the maximum height

When a body thrown vertically up with an initial velocity vo ,then maximum height reached by the body is

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the maximum height reached.

For a body thrown vertically up with an initial velocity u ,the maximum height reached by body from the ground is

A stone thrown vertically upwards rises S ft in t seconds where S =112t-16t ^(2) . The maximum height reached by the stone is

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-

A particle is thrown vertically upward from the ground with some velocity and it strikes the ground again in time 2 s. The maximum height achieved by the particle is : (g=10 m//s^(2))