Correct statements in the following are A) For a freely falling body, velocity acquired is proportional to square root of height of fall B) For a freely falling body ratio of displacement in successive equal intervals of time is 1:4:9 C) For a body projected up, displacement during last second of upward journey is independent of velocity of projection A) A.B B) A.C C) A.B.C D) B.C

Assertion: If a body is dropped from the top of a twoer of height h and another body is thrown up simultaneously with velocity u from the foot of the tower, then both of them would meet after a time (h)/(u) . Reason: For a body projected upwards, the distance covered by the body in the last second of its upwards journey is always 4.9m irrespective of velocity of projection (g=9.8 m//s^(2))

A body projected up with certain velocity travels distance 'y' in the last second of total journey. If velocity of projection is doubled, distance travelled in last second of total journey is - A) 2y B) 2y - g C) 2y +g D) 2y+g/2

(a) If ratio are made to fall of two bodies is 1: 2, what is the ratio of their heights of fall ? (b) Two bodies are made to fall from two different height in the ratio 9:4 . What will be the ratio of their times of fall ?

Consider following speed time graphs describing motion of two bodies A and B on straight line paths. Form these graphs which of the following information can certainly be obtained? (A) Distance travelled for the body A (B) Distance travelled for the body B (C) Displacement for the body A (D) Didplacement for the body B

A body oscillates with SHM according to the equation x(t)=5cos(2pit+pi//4) where t is in second and x in metres. Calculate (a) displacement at t=0 (b) time period (c) initial velocity

The distance travelled by a body during last second of its total flight is d when the body is projected vertically up with certain velocity. If the velocity of projection is doubled, the distance travelled by the body during last second of its total flight is (A) 2d (B) d (C) 2d + g/2 (D) 2d –g/2