[" Two blocks "A&B" ,placed on floor as "],[" shown."M_(A)=10kg.M_(B)=20kg],[" Coefficient of friction between "A&B],[=mu_(AB)=0.2" coefficient of friction "],[" between "B&" ground "=mu_(Bg)=0.1],[F_(1)=20N&F_(2)=70N" are acting "],[" blocks as shown.Find the friction in "],[" b/w the blocks."],[qquad A]

If coefficient of friction between both the block is mu- (1)/(2) . Find friction force acting between both block.

In the arrangement shown in figure, coefficient of friction between the two blocks is mu=1//2 . The force of friction acting between

Two blocks of masses 2 kg and 4kg are connected through a massless inextensible string. The co-efficient of fricition between 2kg block and ground is 0.4 and the coefficient of friction between 4kg block and ground is 0.6. The forces F_(1)=10N and F_(2)=20N are applied on the blocks as shown in the figure. Calculate the frictional force between 4 kg block and ground (Assume initially the tension in the string was just before forces F_(1) and F_(2) wer applied).

m=20 kg, mu_(s)=0.5 , find friction on block.

Two blocks A and B are lying on the table as shown in the figure. The coefficient of friciton between block A and block B is mu . The coefficient of friction between block B and ground also mu . An external force F is applied in the direction shown. The maximum value of the force F that can be applied without moving the blocks.

Block A of mass 2kg is placed over a block B of mass 8kg . The combination is placed on a rough horizontal surface. If g=10ms^(-2) , coefficient of friction between B and floor =0.5 , coefficient of friction between B and floor =0.5 , coefficient of friction between A and B=0.4 and a horizontal force of 10N is applied on 8kg block, then the force of friction between A and B is.

Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of upper block is

Block B rests on a smooth surface .The coefficient of static friction between A and B is mu = 0.4 where F = 30 N then Acceleration of lower block is

Block B of mass m_(B) = 0.5 kg rests on block A, with mass m_(A) = 1.5kg which in turn is on a horizontal tabletop (as shown in figure) .The coefficient of kinetic friction between block A and the tabletop is mu_(k) = 0.4 and the coefficient of static friction between block A and blockB is mu_(s) = 0.6 A light string attached block A passes over a frictionless, massless pulley and block C is suspeneded from the other end of the string. What is the largest mass m_(c) (in kg) that block C can have so that block A and B still slide together when the system is relaced from rest?