A particle starts from rest at `t=0` and moves along a straight line with a variable acceleration given by a `(t)=(3t+1)ms^(-2)` ,where `t],[` is in seconds.The velocity of the particle at `t=4s` is

A particle starts from rest at t=0 and moves in a straight line with an acceleration as shown below. The velocity of the particle at t=3 s is

A particle starts from rest, moving in a straight line with a time varying acceleration ( "in"m//s^(2) ): a= 30 -(15)/(2) sqrt(t) , where time is in seconds . The displacement of the particle in 4 seconds is .

A car moves along a straight line whose equation of motion is given by s=12t+3t^(2)-2t^(3) where s is in metres and t is in seconds. The velocity of the car at start will be :-

The position of the particle moving along x-axis is given by x=2t-3t^(2)+t^(3) where x is in mt and t is in second.The velocity of the particle at t=2sec is

A particle starts from the origin with a velocity of 10 and moves along a straight line.If its acceleration be (2t^(2)-3t)(cm)/(s^(2)) at the end of t seconds,then find its velocity and the distance from the origin at the end of 6seconds

Starting from rest a particle moves in a straight line with acceleration a = (25 - t^(2))^(1//2) m//s^(2) " for " 0 le t le 5s a = (3pi)/(8) m//s^(2) " for " t gt 5s The velocity of particle at t = 7 s is:

A particle moves along a straight line such that its displacement at any time t is given by s = 3t^(3)+7t^(2)+14t + 5 . The acceleration of the particle at t = 1s is

A particle moves along a straight line such that its displacement s at any time t is given by s=t^3-6t^2+3t+4m , t being is seconds. Find the velocity of the particle when the acceleration is zero.