Two block "A&B" of mass `M_(A)=1kg&M_(B)=3kg` are kept on a smooth table as shown in the figure.The coefficient of friction between "A&B" is "0.2" .The maximum force "F" that can be applied on "B" horizontally,so that the block "A" do not slide over the block "B" is Take `g=10m/s^(2)andk=400N/m)`

Two blocks A and B of masses m_(A) = 1kg and m_(B) = 3kg are kept on the table as shown in figure. The coefficient of friction between A and B is 0.2 and between B and the surface of the table is also 0.2. The maximum force F that can be applied on B horizontally, so that the block A does not slide over the block B is ________ (in N): [Take g = 10 m//s^(2) ]

Two block A and B of masses 5 kg. and 3 kg. respectively rest on smooth horizontal surface with B over A. The coefficient of friction between A and B. 0.5 the maximum horizontal force that can be applied to A so that there will be motion of A and B without separation is :-

A block of mass m is placed on another block of mass M lying on a smooth horizontal surface as shown in the figure. The co-efficient of friction between the blocks is mu . Find the maximum horizontal force F (in Newton) that can be applied to the block M so that the blocks together with same acceleration? (M=3kg, m=2kg, mu=0.1, g=10m//s^(2))

Two block A and B of mass 50 kg and 300 kg respectively are placed as shown in figure. Coefficient of friction between all surface is (1)/(2) Then (take g = 10 m//s )

In the arrangement shown in figure m_(A)=m_(B) =2 kg . String is massless and pulley is frictionless. Block B is resting on a smooth horizontal surface, while friction coefficient between blocks A and B is mu=0.5 . What maximum horizontal force F can be applied so that block A does not slip over the block B? (g=10 m//s^(2))

A rectangular block of mass 5 kg is kept on a horizontal surface . The coefficient of friction between the block and the surface is 0.2 . If a force of 20 N is applied to the block at angle of 30^(@) with the horizontal plane , what is the force of friction on the block ? (Take g = 10 m//s^(2) )

Block A of mass 5 kg is resting on a frictionless floor. Another block B of mass 7kg is resting on it as shown in the figure. The coefficient of friction between the blocks is 0.5 while kinetic friction is 0.4. If a force of 100 N is applied to block B, the acceleration of the block A will be ( g =10 ms^(-2)) :