If a carrier wave `c(t)=A sin omega_(c)t` is amplitude modulated by a modulator signal `m(t)=A sin omega_(m)t` then the equation of modulated signal `[C_(m)(t)]` and its modulation index are respectively

A carrier wave c(t)=A_(c) sin omega_(c) t is amplitude modulated by a modulating signal m(t)=A_(m) sin omega_(m) t . The maximum and minimum amplitudes are found to be 16 V and 4 V , respectively. Calculate the modulation index.

Equation of messages signal m = 2 sin omega_(m)(t) and carrier signal c = 4 sin omega_(C)(t) . The equation of modulating signal will be

A sinusoidal carrier wave of amplitude 40 V is amplitude modulated by a sinusoidal signal voltage. What is the amplitude of each side band if the modulation index is 25%.

A carrier signal C(t)=25 sin(2.512xx10^(10)t) is amplitude modulated by a message signal m(t)=5 sin(1.57 xx 10^(8)t) and transmitted through an antenna. What will be the bandwidth of the modulated signal ?

An audio signal represented as 25 sin 2pi ( 2000 t) amplitude modulated by a carrier wave : 60 sin 2pi (100,000)t . The modulation index of the modulated signal is

In amplitude modulation equation of mesenger wave A_(o)sinomega_(m)t and carrier wave A_(C)cosomega_(C)t the equation of amplitude modulated wave is

If A_m and A_c are the amplitudes of modulating signal and carrier wave respectively, then modulation index is given by

The amplitude modulated current is given by i=70[1+0.06sin2900t]sin10^(6)t . The depth of modulation is

The amplitude modulated current is given by i=125[1+0.6sin2900t]sin10^(6)t . The depth of modulation is