Home
Class 11
PHYSICS
The horizontal and vertical displacemen...

The horizontal and vertical displacements of a projectile at time t are x=36t and `y=48t-4.9t^(2)` respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

Answer

Step by step text solution for The horizontal and vertical displacements of a projectile at time t are x=36t and y=48t-4.9t^(2) respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is by PHYSICS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

The horizontal and vertical distances covered by a projectile at tiem t are given by x=at and y= bt^(2)+ct , wehre a,b and c are constants. What is the magnitude of the velocity of the projectile 1 second after it is fired?

The vertical and horizontal displacements of a projectile thrown from a point on the ground at time t are given by y=6t-5t^(2) and x=8t respectively,where x and y are in meters and t is in seconds.The time of flight of the projectile in seconds is ?

Knowledge Check

  • The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

    A
    9.6
    B
    10.6
    C
    19.2
    D
    38.4
  • The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

    A
    `5m//s^(2)`
    B
    `-4m//s^(2)`
    C
    `-8m//s^(2)`
    D
    `0`
  • The 'x' and 'y' coordinates of the particle at any time are 'x'=5t-2t^(2) and 'y'=10t , respectively. Where 'x' and 'y' are in metres and 't' in seconds The acceleration of the particle at t=2 s is :

    A
    `5"m/s"^(2)`
    B
    `-4"m/s"^(2)`
    C
    `-8"m/s"^(2)`
    D
    `0`
  • Similar Questions

    Explore conceptually related problems

    The x and y coordinates of the particle at any time are x=5t-2t^(2) and y = 10t respectively, where x andy are in metres and / in seconds. The acceleration of the particle at t = 5 s is

    The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is

    The x and y coordinates of a particle at any time t is given by x = 7t + 4t^(2) and y = 5t , where x and y are in metre and t in seconds. The acceleration of particle at t = 5s is

    The horizontal and vertical distances travelled by a particle in time t are given by x=6t and y=8t-5t^(2) . If g= 10m//sec^(2) , then the initial velocity of the particle is

    The displacement of a particle executing S.H.M. is given by y = 10 sin [6t + (pi)/(3)] where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle is