The horizontal and vertical displacements of a projectile at time t are x=36t and `y=48t-4.9t^(2)` respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

The horizontal and vertical distances covered by a projectile at tiem t are given by x=at and y= bt^(2)+ct , wehre a,b and c are constants. What is the magnitude of the velocity of the projectile 1 second after it is fired?

The vertical and horizontal displacements of a projectile thrown from a point on the ground at time t are given by y=6t-5t^(2) and x=8t respectively,where x and y are in meters and t is in seconds.The time of flight of the projectile in seconds is ?

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y = 10t respectively, where x andy are in metres and / in seconds. The acceleration of the particle at t = 5 s is

The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is

The horizontal and vertical distances travelled by a particle in time t are given by x=6t and y=8t-5t^(2) . If g= 10m//sec^(2) , then the initial velocity of the particle is

The displacement of a particle executing S.H.M. is given by y = 10 sin [6t + (pi)/(3)] where y is in metres and t is in seconds. Then the initial displacement and velocity of the particle is