A prism is made of glass of unknown refractive index.A parallel beam of light is incidence on the first refracting face of prism.The angle of minimum deviation is measured to be `40^(@)` .What is the refractive index of material of the prism? The refracting angle of prism is `60^(@)`. [`sin50^(@)`=0.766]]

A prism is made of glass of unknown refractive index. A parallel beam of light is incident on a face of the prism. By rotating the prism, the minimum angle of deviation is measured to be 40^@ . What is the refractive index of the prism ? If the prism is placed in water (mu = 1.33) , predict the new angle of minimum deviation of the parallel beam. The refracting angle of prism is 60^@ .

The angle of minimum deviation for prism of angle pi//3 is pi//6 . The refractive index of the material of the prism is.

If the angle of minimum deviation is of 60^@ for an equilateral prism , then the refractive index of the material of the prism is

The angle of minimum deviation produced by a 60^(@) prism is 40^(@) . Calculate the refractive index of the material of the prism.

The angle of the prism is A and B if the angle of minimum deviation is (180^(@) - 2A) then the refractive index of the material of the prism is

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of that prism is

The angle of minimum deviation of a prism of refractive index sqrt(3) is equal to its refracting angle. Then the refracting angle of the prism is

The refractive angle of a prism is 60^(@) . What is the angle of minimum deviation, if the refractive index of the material of the prism is sqrt2 ?