Let p be a point on the parabola `y^(2)=4ax` then the abscissa of p ,the ordinates of p and the latus rectum are in

If the normals at two points P and Q of a parabola y^2 = 4x intersect at a third point R on the parabola y^2 = 4x , then the product of the ordinates of P and Q is equal to

If "P" is a point on the parabola " y^(2)=4ax " in which the abscissa is equal to ordinate then the equation of the normal at "P" is

If focal distance of a point P on the parabola y^(2)=4ax whose abscissa is 5 10, then find the value of a.

If focal distance of a point P on the parabola y^(2)=4ax whose abscissa is 5 10, then find the value of a.

The point P(9/2,6) lies on the parabola y^(2)=4ax then parameter of the point P is:

Normal at a point P on the parabola y^(2)=4ax meets the axis at Q such that the distacne of Q from the focus of the parabola is 10a. The coordinates of P are :

" The ordinate of a point on the parabola " y^(2)=18x " is one third of its length of the latus rectum. Then the length of subtangent at the point is "

P is a point on the axis of the parabola y^(2)=4ax , Q and R are the extremities of its latus rectum, A is its vertex. If PQR is an equilateral triangle lying within the parabola and /__ AQP= theta , then cos theta=

The normal meet the parabola y^(2)=4ax at that point where the abscissa of the point is equal to the ordinate of the point is