Equation of the circle passing through `A(1,2), B(5,2)` such that the angle subtended by AB at points the circle is `pi/4` is (A) `x^2+y^2-6x-8=0` (B) `x^2+y^2-6x-8y+17=0` (C) `x^2+y^2 -6x+8=0` (D) `x^2+y^2-6x+8y-25=0`

The equation of the circle which inscribes a suqre whose two diagonally opposite vertices are (4, 2) and (2, 6) respectively is : (A) x^2 + y^2 + 4x - 6y + 10 = 0 (B) x^2 + y^2 - 6x - 8y + 20 = 0 (C) x^2 + y^2 - 6x + 8y + 25 = 0 (D) x^2 + y^2 + 6x + 8y + 15 = 0

The equation of the circle passing through the point of intersection of the circles x^2 + y^2 - 6x + 2y + 4 = 0 and x^2 + y^2 + 2x - 6y - 6=0 and having its centre on y=0 is : (A) 2x^2 + 2y^2 + 8x + 3 = 0 (B) 2x^2 + 2y^2 - 8x - 3 = 0 (C) 2x^2 + 2y^2 - 8x + 3 = 0 (D) none of these

The circles x^(2)+y^(2)-6x-8y=0 and x^(2)+y^(2)-6x+8=0 are

Find the equation of the circle passing through the centre of the circle x^2 +y^2 -4x-6y=8 and being concentric with the circle x^2 +y^2 - 2x-8y=5 .

Tangents drawn from the point P(1,8) to the circle x^(2)+y^(2)-6x-4y-11=0 touch the circle at the points A and B. The equation of the circumcircle of the triangle PAB is (A) x^(2)+y^(2)+4x-6y+19=0 (B) x^(2)+y^(2)-4x-10y+19=0 (B) x^(2)+y^(2)-2x+6y-29=0 (D) x^(2)+y^(2)-6x-4y+19=0

(3,-4) is the point to which the origin is shifted and the transformed equation is X^(2)+Y^(2)=4 then the original equation is (A) x^(2)+y^(2)+6x+8y+21=0 (B) x^(2)+y^(2)+6x+8y-21,=0 (C) x^(2)+y^(2)-6x+8y+21=0 (D) x^(2)+y^(2)-6x-8y+21=0

Find the equation of the circle passing through the centre of the circle x^(2)+y^(2)+8x+10y-7=0 and concentric with the circle x^(2)+y^(2)-4x-6y=0