The line `sqrt(2y)-2x+8a=0` is a normal to the parabola `y^(2)=4ax` at P ,then P=

The line sqrt(2)y-2x+8a=0 is a normal to the parabola y^(2)=4ax at P .then P =

The line 2x+y+lamda=0 is a normal to the parabola y^(2)=-8x, is lamda =

The line 1x+my+n=0 is a normal to the parabola y^(2)=4ax if :

The line lx+my+n=0 is a normal to the parabola y^(2)=4ax if

Statement 1: The line ax+by+c=0 is a normal to the parabola y^(2)=4ax. Then the equation of the tangent at the foot of this normal is y=((b)/(a))x+((a^(2))/(b)). Statement 2: The equation of normal at any point P(at^(2),2at) to the parabola y^(2)= 4ax is y=-tx+2at+at^(3)

If the line y=mx+c is a normal to the parabola y^2=4ax , then c is

If y=x+2 is normal to the parabola y^(2)=4ax, then find the value of a.

Prove that the chord y-x sqrt(2)+4a sqrt(2)=0 is a normal chord of the parabola y^(2)=4ax . Also find the point on the parabola when the given chord is normal to the parabola.