A body thrown with a speed `10ms^(-1)` vertically upwards from ground reaches the ground with a speed `8ms^(-1)` . Then the maximum height reached by the body is

A ball is thrown vertically upwards with a velocity of 10 ms^(-1) . It returns to the ground with a velocity of 9 ms^(-1) . If g=9.8 ms^(-2) , then the maximum height attained by the ball is nearly (assume air resistance to be uniform)

A stone is thrown vertically upwards with a velocity of 4.9 ms^(-1) . Calculate : the maximum height reached.

A stone is thrown vertically upwards. When stone is at a height half of its maximum height, its speed is 10 ms^-1 , then the maximum height attained by the stone is ( g= 10 ms^(-2) )

A ball is thrown upwards with speed v from the top of a tower and it reaches the ground with speed 3v .The height of the tower is

A ball is thrown upwards with speed ‘v’ from the top of a tower and it reaches the ground with a speed 3v, then the height of the tower is

A body is projected upwards under gravity with a speed of 19.6 Then, maximum height which can be reached is

A stone is thrown vertically upwards with an initial speed u from the top of a tower, reaches the ground with a speed 3 u . The height of the tower is :

A stone thrown upward with a speed u from the top of a tower reaches the ground with a velocity 4u. The height of the tower is

When a body is projected vertically up from ground, its velocity is reduced to 1/3 rd of initial velocity at height 'y' above the ground. Then maximum height reached by the body is