Let `|x-2|+|x|+|x+3|=k` ,have real solution then possible value of `k` is are

Let f(x)=x+2|x+1|+2|x-1|* If f(x)=k has exactly one real solution,then the value of k is (a) 3 (b) 0(c)1(d)2

If the equation x^2-kx+3=0 has a real solution, then least integer value of k is

If x^2 + kx + k =0 has two distinct real solutions, then the value of k will satisfy:

The equation k+x^(3)e^(x+3)=0 has 2 distinct real roots & k is a prime natural number, then the possible value of k is/are

For the quadratic equation, x^2+kx+k to have imaginary roots, the possible values of k are?

Let f:R rarr R be defined by, f(x)={[k-x;x le-1],[x^(2)+3,,xgt-1] .If f(x) has least value at x=-1 , then the possible value of k is

Given that |x+1|+|x+2|+|x+3)|=k where k is real number then: value of k for which equation has one solution:

Let f:R to R be defined by f(x)={{:(2k-2x",",ifxle-1),(2x+3",",iffxgt-1):} If f has a local minimum at x=-1, then a possible value of k is

The system of equations 2x-ay=45x-ky=5 is in consistant with no unique solution.If k and a are natural numbers,then the minimum possible value of (a+k) is equal to

Let f:""RrarrR be defined by f(x)={(k-2x , if xle-1),( 2x+3, if x gt-1):} . If f has a local minimum at x""=""-1 , then a possible value of k is