" Time constant of charging of capacitor is equal to "(30.8)/(N)C" .Find "N

The time constant of charging of the capacitor charging of the capacitor shown in figure is

The time constant, for charging of capacitor C, when switch S is closed as shown in the figure , is

Find (a) equivalent time constant, (b) charge on capacitor in terms of time t.

A capacitor of capacitance C_(o) is charged to a potential V and then isolated. A small capacitor C is then charged from C_(o) , discharged and charged again, the process being repeated n times. Due to this, potential of the large capacitor is decreased to V . Find the capacitance of the small capacitor :

A capacitor of capacitance C is having a charge Q_(0) . It is connected to a pure inductor of inductance L. The inductor is a solenoid having N turns. Find the magnitude of magnetic flux through each of the N turns in the coil at the instant charge on the capacitor becomes (Q_(0))/(2) .

A capacitence of C_(0) is charged to a potential V_(0) and then isolated. A small cpacitor C is then charged from C_(0) , discharged and charged again, the process bing repeated n times. Due to this, potential of the large capacitor is decreased to V . find the capacitance of the small capacitor. is it possible to remove charge on C_(0) completely in this way?

During charging of capacitor find time when potential drop across capacitor is equal to potential drop across resistance :-

The heat produced by a resistor in any time t during the charging of a capacitor in a series circuit is half the energy stored in the capacitor by that time. Current in the circuit is equal to the rate of increase in charge on the capacitor.